image-20241108031219233

思路

8多说,直接遍历

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char* str(char*s){
  int len=strlen(s);
  char *res=(char *)malloc(2*len+1);
  int j=0;
  for(int i=0;i<len;i++){
    if(s[i]==' '){
      res[j++] = '%';
      res[j++] = '2';
      res[j++] = '0';
    }else{
      res[j++]=s[i];
    }
  }
  res[j]='\0';
  return res;
}